1221311250133 has 4 divisors (see below), whose sum is σ = 1315258269388. Its totient is φ = 1127364230880.

The previous prime is 1221311250119. The next prime is 1221311250169. The reversal of 1221311250133 is 3310521131221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 411755789124 + 809555461009 = 641682^2 + 899753^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1221311250133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1221311250098 and 1221311250107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1221311250433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46973509608 + ... + 46973509633.

It is an arithmetic number, because the mean of its divisors is an integer number (328814567347).

Almost surely, 2^{1221311250133} is an apocalyptic number.

1221311250133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1221311250133 is a deficient number, since it is larger than the sum of its proper divisors (93947019255).

1221311250133 is an equidigital number, since it uses as much as digits as its factorization.

1221311250133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93947019254.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 1221311250133 its reverse (3310521131221), we get a palindrome (4531832381354).

The spelling of 1221311250133 in words is "one trillion, two hundred twenty-one billion, three hundred eleven million, two hundred fifty thousand, one hundred thirty-three".