Base | Representation |
---|---|
bin | 1011000110111001011011… |
… | …1000000110100110010111 |
3 | 1121020120012120012010001022 |
4 | 2301232112320012212113 |
5 | 3100044434031441043 |
6 | 41550344214151355 |
7 | 2400240403201304 |
oct | 261562670064627 |
9 | 47216176163038 |
10 | 12213123312023 |
11 | 3989613794617 |
12 | 1452b9a35255b |
13 | 6a79007c703a |
14 | 3031929680ab |
15 | 162a58553868 |
hex | b1b96e06997 |
12213123312023 has 2 divisors, whose sum is σ = 12213123312024. Its totient is φ = 12213123312022.
The previous prime is 12213123311927. The next prime is 12213123312073. The reversal of 12213123312023 is 32021332131221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12213123312023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12213123311983 and 12213123312001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12213123312073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106561656011 + 6106561656012.
It is an arithmetic number, because the mean of its divisors is an integer number (6106561656012).
Almost surely, 212213123312023 is an apocalyptic number.
12213123312023 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213123312023 is an equidigital number, since it uses as much as digits as its factorization.
12213123312023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 12213123312023 its reverse (32021332131221), we get a palindrome (44234455443244).
The spelling of 12213123312023 in words is "twelve trillion, two hundred thirteen billion, one hundred twenty-three million, three hundred twelve thousand, twenty-three".
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