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12213131133239 is a prime number
BaseRepresentation
bin1011000110111001011101…
…0101111100000100110111
31121020120020002220110201222
42301232113111330010313
53100044443032230424
641550345053540555
72400240526524551
oct261562725740467
947216202813658
1012213131133239
113989618146833
121452ba0aa475b
136a7902304c8a
14303193a024d1
15162a5909ae5e
hexb1b9757c137

12213131133239 has 2 divisors, whose sum is σ = 12213131133240. Its totient is φ = 12213131133238.

The previous prime is 12213131133199. The next prime is 12213131133241. The reversal of 12213131133239 is 93233113131221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12213131133239 - 220 = 12213130084663 is a prime.

It is a super-2 number, since 2×122131311332392 (a number of 27 digits) contains 22 as substring.

Together with 12213131133241, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12213131133199 and 12213131133208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12213131138239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106565566619 + 6106565566620.

It is an arithmetic number, because the mean of its divisors is an integer number (6106565566620).

Almost surely, 212213131133239 is an apocalyptic number.

12213131133239 is a deficient number, since it is larger than the sum of its proper divisors (1).

12213131133239 is an equidigital number, since it uses as much as digits as its factorization.

12213131133239 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17496, while the sum is 35.

The spelling of 12213131133239 in words is "twelve trillion, two hundred thirteen billion, one hundred thirty-one million, one hundred thirty-three thousand, two hundred thirty-nine".