Base | Representation |
---|---|
bin | 1011000110111001101110… |
… | …0000110110100101111110 |
3 | 1121020120101222120022112010 |
4 | 2301232123200312211332 |
5 | 3100100113440300410 |
6 | 41550400033352050 |
7 | 2400242336334651 |
oct | 261563340664576 |
9 | 47216358508463 |
10 | 12213201103230 |
11 | 3989653697276 |
12 | 1453000408626 |
13 | 6a7913962c3a |
14 | 30319d017898 |
15 | 162a602bcc20 |
hex | b1b9b83697e |
12213201103230 has 32 divisors (see below), whose sum is σ = 29313024920064. Its totient is φ = 3256704486176.
The previous prime is 12213201103189. The next prime is 12213201103289. The reversal of 12213201103230 is 3230110231221.
It is a junction number, because it is equal to n+sod(n) for n = 12213201103197 and 12213201103206.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8654514 + ... + 9966293.
It is an arithmetic number, because the mean of its divisors is an integer number (916032028752).
Almost surely, 212213201103230 is an apocalyptic number.
12213201103230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12213201103230 is an abundant number, since it is smaller than the sum of its proper divisors (17099823816834).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12213201103230 is a wasteful number, since it uses less digits than its factorization.
12213201103230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18642680.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 12213201103230 its reverse (3230110231221), we get a palindrome (15443311334451).
The spelling of 12213201103230 in words is "twelve trillion, two hundred thirteen billion, two hundred one million, one hundred three thousand, two hundred thirty".
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