Base | Representation |
---|---|
bin | 1011000110111010001000… |
… | …1000101111100000001111 |
3 | 1121020120200201122210112022 |
4 | 2301232202020233200033 |
5 | 3100100330412120442 |
6 | 41550415043200355 |
7 | 2400245156003012 |
oct | 261564210574017 |
9 | 47216621583468 |
10 | 12213312223247 |
11 | 39897003933a3 |
12 | 14530316760bb |
13 | 6a793099b025 |
14 | 3031adaa1379 |
15 | 162a69e1c3d2 |
hex | b1ba222f80f |
12213312223247 has 2 divisors, whose sum is σ = 12213312223248. Its totient is φ = 12213312223246.
The previous prime is 12213312223199. The next prime is 12213312223249. The reversal of 12213312223247 is 74232221331221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12213312223247 - 224 = 12213295446031 is a prime.
It is a super-3 number, since 3×122133122232473 (a number of 40 digits) contains 333 as substring.
Together with 12213312223249, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12213312223249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106656111623 + 6106656111624.
It is an arithmetic number, because the mean of its divisors is an integer number (6106656111624).
Almost surely, 212213312223247 is an apocalyptic number.
12213312223247 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213312223247 is an equidigital number, since it uses as much as digits as its factorization.
12213312223247 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48384, while the sum is 35.
Adding to 12213312223247 its reverse (74232221331221), we get a palindrome (86445533554468).
The spelling of 12213312223247 in words is "twelve trillion, two hundred thirteen billion, three hundred twelve million, two hundred twenty-three thousand, two hundred forty-seven".
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