Base | Representation |
---|---|
bin | 1011000110111010001010… |
… | …1010101100010100011111 |
3 | 1121020120201100101221211121 |
4 | 2301232202222230110133 |
5 | 3100100340201414403 |
6 | 41550420002031411 |
7 | 2400245324441062 |
oct | 261564252542437 |
9 | 47216640357747 |
10 | 12213321123103 |
11 | 3989705411a51 |
12 | 1453034648567 |
13 | 6a7932795c09 |
14 | 3031b0d3a8d9 |
15 | 162a6aac93bd |
hex | b1ba2aac51f |
12213321123103 has 2 divisors, whose sum is σ = 12213321123104. Its totient is φ = 12213321123102.
The previous prime is 12213321123001. The next prime is 12213321123109. The reversal of 12213321123103 is 30132112331221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12213321123103 - 29 = 12213321122591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12213321123109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106660561551 + 6106660561552.
It is an arithmetic number, because the mean of its divisors is an integer number (6106660561552).
Almost surely, 212213321123103 is an apocalyptic number.
12213321123103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213321123103 is an equidigital number, since it uses as much as digits as its factorization.
12213321123103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 12213321123103 its reverse (30132112331221), we get a palindrome (42345433454324).
The spelling of 12213321123103 in words is "twelve trillion, two hundred thirteen billion, three hundred twenty-one million, one hundred twenty-three thousand, one hundred three".
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