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12214050053 is a prime number
BaseRepresentation
bin10110110000000001…
…11001110100000101
31011112012220000211012
423120000321310011
5200003244100203
65335553252005
7611450466242
oct133000716405
934465800735
1012214050053
1151a8570647
12244a564005
1311c85cac6a
1483c21a5c9
154b7452bd8
hex2d8039d05

12214050053 has 2 divisors, whose sum is σ = 12214050054. Its totient is φ = 12214050052.

The previous prime is 12214050049. The next prime is 12214050071. The reversal of 12214050053 is 35005041221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7016072644 + 5197977409 = 83762^2 + 72097^2 .

It is an emirp because it is prime and its reverse (35005041221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12214050053 - 22 = 12214050049 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12214050253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6107025026 + 6107025027.

It is an arithmetic number, because the mean of its divisors is an integer number (6107025027).

Almost surely, 212214050053 is an apocalyptic number.

It is an amenable number.

12214050053 is a deficient number, since it is larger than the sum of its proper divisors (1).

12214050053 is an equidigital number, since it uses as much as digits as its factorization.

12214050053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 12214050053 its reverse (35005041221), we get a palindrome (47219091274).

The spelling of 12214050053 in words is "twelve billion, two hundred fourteen million, fifty thousand, fifty-three".