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122141035 = 5107228301
BaseRepresentation
bin1110100011110…
…11100101101011
322111211102000001
413101323211223
5222232003120
620041523431
73012116212
oct721734553
9274742001
10122141035
1162a44405
1234aa3577
131c3c6603
1412316079
15aac9e0a
hex747b96b

122141035 has 8 divisors (see below), whose sum is σ = 147939696. Its totient is φ = 96799200.

The previous prime is 122140999. The next prime is 122141053. The reversal of 122141035 is 530141221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 122141035 - 211 = 122138987 is a prime.

It is a super-3 number, since 3×1221410353 (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 113616 + ... + 114685.

It is an arithmetic number, because the mean of its divisors is an integer number (18492462).

Almost surely, 2122141035 is an apocalyptic number.

122141035 is a deficient number, since it is larger than the sum of its proper divisors (25798661).

122141035 is a wasteful number, since it uses less digits than its factorization.

122141035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 228413.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 122141035 is about 11051.7435276069. The cubic root of 122141035 is about 496.1586096871.

Adding to 122141035 its reverse (530141221), we get a palindrome (652282256).

The spelling of 122141035 in words is "one hundred twenty-two million, one hundred forty-one thousand, thirty-five".

Divisors: 1 5 107 535 228301 1141505 24428207 122141035