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122200007 is a prime number
BaseRepresentation
bin1110100100010…
…01111111000111
322111221101220012
413102021333013
5222240400012
620043100435
73012453146
oct722117707
9274841805
10122200007
1162a84746
1234b1171b
131c4173c7
141232d75d
15aadc622
hex7489fc7

122200007 has 2 divisors, whose sum is σ = 122200008. Its totient is φ = 122200006.

The previous prime is 122200003. The next prime is 122200021. The reversal of 122200007 is 700002221.

It is an a-pointer prime, because the next prime (122200021) can be obtained adding 122200007 to its sum of digits (14).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 122200007 - 22 = 122200003 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 122199964 and 122200000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122200003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61100003 + 61100004.

It is an arithmetic number, because the mean of its divisors is an integer number (61100004).

Almost surely, 2122200007 is an apocalyptic number.

122200007 is a deficient number, since it is larger than the sum of its proper divisors (1).

122200007 is an equidigital number, since it uses as much as digits as its factorization.

122200007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 14.

The square root of 122200007 is about 11054.4112009641. The cubic root of 122200007 is about 496.2384484238.

Adding to 122200007 its reverse (700002221), we get a palindrome (822202228).

The spelling of 122200007 in words is "one hundred twenty-two million, two hundred thousand, seven".