Base | Representation |
---|---|
bin | 1011000111010011000101… |
… | …1010111011110001001001 |
3 | 1121021012222120210001121021 |
4 | 2301310301122323301021 |
5 | 3100203040320220012 |
6 | 41553443503312441 |
7 | 2400603160350421 |
oct | 261646132736111 |
9 | 47235876701537 |
10 | 12220011101257 |
11 | 3991528767613 |
12 | 14543a0bab721 |
13 | 6a845a7a257b |
14 | 303647635481 |
15 | 162d0d0a5007 |
hex | b1d316bbc49 |
12220011101257 has 2 divisors, whose sum is σ = 12220011101258. Its totient is φ = 12220011101256.
The previous prime is 12220011101213. The next prime is 12220011101261. The reversal of 12220011101257 is 75210111002221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11523180165561 + 696830935696 = 3394581^2 + 834764^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12220011101257 is a prime.
It is not a weakly prime, because it can be changed into another prime (12220011101657) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110005550628 + 6110005550629.
It is an arithmetic number, because the mean of its divisors is an integer number (6110005550629).
Almost surely, 212220011101257 is an apocalyptic number.
It is an amenable number.
12220011101257 is a deficient number, since it is larger than the sum of its proper divisors (1).
12220011101257 is an equidigital number, since it uses as much as digits as its factorization.
12220011101257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 560, while the sum is 25.
Adding to 12220011101257 its reverse (75210111002221), we get a palindrome (87430122103478).
The spelling of 12220011101257 in words is "twelve trillion, two hundred twenty billion, eleven million, one hundred one thousand, two hundred fifty-seven".
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