Base | Representation |
---|---|
bin | 1011000111010111100110… |
… | …0010101101101000011111 |
3 | 1121021100002220121100220212 |
4 | 2301311321202231220133 |
5 | 3100213030100200223 |
6 | 41554203530003035 |
7 | 2400645152231633 |
oct | 261657142555037 |
9 | 47240086540825 |
10 | 12221221100063 |
11 | 3991a99782628 |
12 | 145467a27647b |
13 | 6a85c1387bb1 |
14 | 303720208dc3 |
15 | 162d7e418278 |
hex | b1d798ada1f |
12221221100063 has 2 divisors, whose sum is σ = 12221221100064. Its totient is φ = 12221221100062.
The previous prime is 12221221100003. The next prime is 12221221100069. The reversal of 12221221100063 is 36000112212221.
It is a strong prime.
It is an emirp because it is prime and its reverse (36000112212221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12221221100063 - 214 = 12221221083679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12221221100069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110610550031 + 6110610550032.
It is an arithmetic number, because the mean of its divisors is an integer number (6110610550032).
Almost surely, 212221221100063 is an apocalyptic number.
12221221100063 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221221100063 is an equidigital number, since it uses as much as digits as its factorization.
12221221100063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 12221221100063 its reverse (36000112212221), we get a palindrome (48221333312284).
The spelling of 12221221100063 in words is "twelve trillion, two hundred twenty-one billion, two hundred twenty-one million, one hundred thousand, sixty-three".
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