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12221310113 = 110711103903
BaseRepresentation
bin10110110000111001…
…00110010010100001
31011112201112212202022
423120130212102201
5200012123410423
65340413031225
7611566264505
oct133034462241
934481485668
1012221310113
11520167a1a1
122450a85515
1311c9c7065c
1483d18a305
154b7dd8dc8
hex2d87264a1

12221310113 has 4 divisors (see below), whose sum is σ = 12222425088. Its totient is φ = 12220195140.

The previous prime is 12221310083. The next prime is 12221310137. The reversal of 12221310113 is 31101312221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12221310113 - 216 = 12221244577 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12221310091 and 12221310100.

It is not an unprimeable number, because it can be changed into a prime (12221310173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 540881 + ... + 563022.

It is an arithmetic number, because the mean of its divisors is an integer number (3055606272).

Almost surely, 212221310113 is an apocalyptic number.

It is an amenable number.

12221310113 is a deficient number, since it is larger than the sum of its proper divisors (1114975).

12221310113 is a wasteful number, since it uses less digits than its factorization.

12221310113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1114974.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12221310113 its reverse (31101312221), we get a palindrome (43322622334).

The spelling of 12221310113 in words is "twelve billion, two hundred twenty-one million, three hundred ten thousand, one hundred thirteen".

Divisors: 1 11071 1103903 12221310113