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122214003143 is a prime number
BaseRepresentation
bin111000111010010000…
…1011011000111000111
3102200110022012121211212
41301310201123013013
54000243241100033
6132051102122035
711554401613031
oct1616441330707
9380408177755
10122214003143
1147915689491
121b82928031b
13b6a8aac6bb
145cb53cac51
1532a453b748
hex1c7485b1c7

122214003143 has 2 divisors, whose sum is σ = 122214003144. Its totient is φ = 122214003142.

The previous prime is 122214003103. The next prime is 122214003193. The reversal of 122214003143 is 341300412221.

It is a weak prime.

It is an emirp because it is prime and its reverse (341300412221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 122214003143 - 222 = 122209808839 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122214003103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61107001571 + 61107001572.

It is an arithmetic number, because the mean of its divisors is an integer number (61107001572).

Almost surely, 2122214003143 is an apocalyptic number.

122214003143 is a deficient number, since it is larger than the sum of its proper divisors (1).

122214003143 is an equidigital number, since it uses as much as digits as its factorization.

122214003143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 122214003143 its reverse (341300412221), we get a palindrome (463514415364).

The spelling of 122214003143 in words is "one hundred twenty-two billion, two hundred fourteen million, three thousand, one hundred forty-three".