Base | Representation |
---|---|
bin | 1011000111011000011010… |
… | …0101111000001001111011 |
3 | 1121021100200011120100000002 |
4 | 2301312012211320021323 |
5 | 3100214002122032103 |
6 | 41554241350303215 |
7 | 2400653451153356 |
oct | 261660645701173 |
9 | 47240604510002 |
10 | 12221440033403 |
11 | 39920a1317477 |
12 | 145471b657b0b |
13 | 6a8627840c53 |
14 | 30374131929d |
15 | 162d93762488 |
hex | b1d8697827b |
12221440033403 has 4 divisors (see below), whose sum is σ = 12940348270680. Its totient is φ = 11502531796128.
The previous prime is 12221440033391. The next prime is 12221440033417. The reversal of 12221440033403 is 30433004412221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12221440033403 - 28 = 12221440033147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12221440033493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 359454118613 + ... + 359454118646.
It is an arithmetic number, because the mean of its divisors is an integer number (3235087067670).
Almost surely, 212221440033403 is an apocalyptic number.
12221440033403 is a deficient number, since it is larger than the sum of its proper divisors (718908237277).
12221440033403 is an equidigital number, since it uses as much as digits as its factorization.
12221440033403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 718908237276.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 12221440033403 its reverse (30433004412221), we get a palindrome (42654444445624).
The spelling of 12221440033403 in words is "twelve trillion, two hundred twenty-one billion, four hundred forty million, thirty-three thousand, four hundred three".
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