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122220111011231 is a prime number
BaseRepresentation
bin11011110010100010010110…
…010011010001110110011111
3121000202010110200022210102202
4123302202112103101312133
5112004423241404324411
61111535051024442115
734513053200336102
oct3362422623216637
9530663420283382
10122220111011231
1135a41292437632
121185b0aba7933b
1353273cb68554c
1422276b0942739
15e1e35b45083b
hex6f28964d1d9f

122220111011231 has 2 divisors, whose sum is σ = 122220111011232. Its totient is φ = 122220111011230.

The previous prime is 122220111011191. The next prime is 122220111011233. The reversal of 122220111011231 is 132110111022221.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122220111011231 is a prime.

It is a super-2 number, since 2×1222201110112312 (a number of 29 digits) contains 22 as substring.

Together with 122220111011233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122220111011233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61110055505615 + 61110055505616.

It is an arithmetic number, because the mean of its divisors is an integer number (61110055505616).

Almost surely, 2122220111011231 is an apocalyptic number.

122220111011231 is a deficient number, since it is larger than the sum of its proper divisors (1).

122220111011231 is an equidigital number, since it uses as much as digits as its factorization.

122220111011231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 122220111011231 its reverse (132110111022221), we get a palindrome (254330222033452).

The spelling of 122220111011231 in words is "one hundred twenty-two trillion, two hundred twenty billion, one hundred eleven million, eleven thousand, two hundred thirty-one".