Base | Representation |
---|---|
bin | 1011000111011110101001… |
… | …0100001100110101100111 |
3 | 1121021111222202202222220002 |
4 | 2301313222110030311213 |
5 | 3100230413424334002 |
6 | 41555115354331515 |
7 | 2401043065160216 |
oct | 261675224146547 |
9 | 47244882688802 |
10 | 12223113121127 |
11 | 399287a778aa7 |
12 | 1454b07a29b9b |
13 | 6a8833356a9c |
14 | 30385d5d707d |
15 | 162e4059c002 |
hex | b1dea50cd67 |
12223113121127 has 2 divisors, whose sum is σ = 12223113121128. Its totient is φ = 12223113121126.
The previous prime is 12223113121117. The next prime is 12223113121133. The reversal of 12223113121127 is 72112131132221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12223113121127 - 222 = 12223108926823 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12223113121127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12223113121117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111556560563 + 6111556560564.
It is an arithmetic number, because the mean of its divisors is an integer number (6111556560564).
Almost surely, 212223113121127 is an apocalyptic number.
12223113121127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12223113121127 is an equidigital number, since it uses as much as digits as its factorization.
12223113121127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2016, while the sum is 29.
Adding to 12223113121127 its reverse (72112131132221), we get a palindrome (84335244253348).
The spelling of 12223113121127 in words is "twelve trillion, two hundred twenty-three billion, one hundred thirteen million, one hundred twenty-one thousand, one hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.580 sec. • engine limits •