| Base | Representation |
|---|---|
| bin | 1011000111011110101101… |
| … | …0100111110000100100000 |
| 3 | 1121021112000221201121112020 |
| 4 | 2301313223110332010200 |
| 5 | 3100230432301200000 |
| 6 | 41555121202301440 |
| 7 | 2401043362404261 |
| oct | 261675324760440 |
| 9 | 47245027647466 |
| 10 | 12223130100000 |
| 11 | 3992889315526 |
| 12 | 1454b11657880 |
| 13 | 6a8836a20061 |
| 14 | 303861976968 |
| 15 | 162e41d02ba0 |
| hex | b1deb53e120 |
12223130100000 has 288 divisors, whose sum is σ = 40154236339392. Its totient is φ = 3255465600000.
The previous prime is 12223130099993. The next prime is 12223130100001. The reversal of 12223130100000 is 103132221.
12223130100000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is not an unprimeable number, because it can be changed into a prime (12223130100001) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 246275187 + ... + 246324813.
It is an arithmetic number, because the mean of its divisors is an integer number (139424431734).
Almost surely, 212223130100000 is an apocalyptic number.
12223130100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12223130100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20077118169696).
12223130100000 is an abundant number, since it is smaller than the sum of its proper divisors (27931106239392).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12223130100000 is an frugal number, since it uses more digits than its factorization.
12223130100000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50486 (or 50458 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 12223130100000 its reverse (103132221), we get a palindrome (12223233232221).
It can be divided in two parts, 12223130 and 100000, that added together give a triangular number (12323130 = T4964).
The spelling of 12223130100000 in words is "twelve trillion, two hundred twenty-three billion, one hundred thirty million, one hundred thousand".
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