Base | Representation |
---|---|
bin | 1011000111011111000101… |
… | …1000001101010011011111 |
3 | 1121021112022000201221222122 |
4 | 2301313301120031103133 |
5 | 3100231134243042002 |
6 | 41555135230133155 |
7 | 2401046034265064 |
oct | 261676130152337 |
9 | 47245260657878 |
10 | 12223231612127 |
11 | 399293064a048 |
12 | 1454b3b6511bb |
13 | 6a8851a72bc3 |
14 | 30387123cc6b |
15 | 162e4aba56a2 |
hex | b1df160d4df |
12223231612127 has 2 divisors, whose sum is σ = 12223231612128. Its totient is φ = 12223231612126.
The previous prime is 12223231612117. The next prime is 12223231612129. The reversal of 12223231612127 is 72121613232221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12223231612127 - 210 = 12223231611103 is a prime.
Together with 12223231612129, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12223231612129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111615806063 + 6111615806064.
It is an arithmetic number, because the mean of its divisors is an integer number (6111615806064).
Almost surely, 212223231612127 is an apocalyptic number.
12223231612127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12223231612127 is an equidigital number, since it uses as much as digits as its factorization.
12223231612127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 24192, while the sum is 35.
Adding to 12223231612127 its reverse (72121613232221), we get a palindrome (84344844844348).
The spelling of 12223231612127 in words is "twelve trillion, two hundred twenty-three billion, two hundred thirty-one million, six hundred twelve thousand, one hundred twenty-seven".
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