Base | Representation |
---|---|
bin | 10001110011000000011… |
… | …111111100000100000111 |
3 | 11022220202222211220211122 |
4 | 101303000133330010013 |
5 | 130014201034410043 |
6 | 2333501045024155 |
7 | 154234042053332 |
oct | 21630037740407 |
9 | 4286688756748 |
10 | 1223000310023 |
11 | 431742878478 |
12 | 1790383b505b |
13 | 8b436754ccb |
14 | 4329d097619 |
15 | 21c2e05c368 |
hex | 11cc07fc107 |
1223000310023 has 2 divisors, whose sum is σ = 1223000310024. Its totient is φ = 1223000310022.
The previous prime is 1223000310017. The next prime is 1223000310031. The reversal of 1223000310023 is 3200130003221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1223000310023 - 212 = 1223000305927 is a prime.
It is a super-2 number, since 2×12230003100232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1223000309983 and 1223000310010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1223000310073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611500155011 + 611500155012.
It is an arithmetic number, because the mean of its divisors is an integer number (611500155012).
Almost surely, 21223000310023 is an apocalyptic number.
1223000310023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1223000310023 is an equidigital number, since it uses as much as digits as its factorization.
1223000310023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 1223000310023 its reverse (3200130003221), we get a palindrome (4423130313244).
The spelling of 1223000310023 in words is "one trillion, two hundred twenty-three billion, three hundred ten thousand, twenty-three".
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