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12230113133 = 71747159019
BaseRepresentation
bin10110110001111100…
…01011011101101101
31011120100010010020002
423120332023131231
5200021402110013
65341325434045
7612034150340
oct133076133555
934510103202
1012230113133
115206642017
122453a0b925
1311cba33444
148403dc457
154b8a77358
hex2d8f8b76d

12230113133 has 4 divisors (see below), whose sum is σ = 13977272160. Its totient is φ = 10482954108.

The previous prime is 12230113121. The next prime is 12230113151. The reversal of 12230113133 is 33131103221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12230113133 - 24 = 12230113117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12230113183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 873579503 + ... + 873579516.

It is an arithmetic number, because the mean of its divisors is an integer number (3494318040).

Almost surely, 212230113133 is an apocalyptic number.

It is an amenable number.

12230113133 is a deficient number, since it is larger than the sum of its proper divisors (1747159027).

12230113133 is an equidigital number, since it uses as much as digits as its factorization.

12230113133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1747159026.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 12230113133 its reverse (33131103221), we get a palindrome (45361216354).

The spelling of 12230113133 in words is "twelve billion, two hundred thirty million, one hundred thirteen thousand, one hundred thirty-three".

Divisors: 1 7 1747159019 12230113133