Base | Representation |
---|---|
bin | 10001110011000001010… |
… | …000110110011011100111 |
3 | 11022220210212222100021221 |
4 | 101303001100312123213 |
5 | 130014212330211012 |
6 | 2333502223521211 |
7 | 154234256045242 |
oct | 21630120663347 |
9 | 4286725870257 |
10 | 1223013132007 |
11 | 43174a035857 |
12 | 179040759207 |
13 | 8b4392c4194 |
14 | 432a0a74259 |
15 | 21c30241507 |
hex | 11cc14366e7 |
1223013132007 has 2 divisors, whose sum is σ = 1223013132008. Its totient is φ = 1223013132006.
The previous prime is 1223013131897. The next prime is 1223013132097. The reversal of 1223013132007 is 7002313103221.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1223013132007 is a prime.
It is a super-2 number, since 2×12230131320072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1223013132097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611506566003 + 611506566004.
It is an arithmetic number, because the mean of its divisors is an integer number (611506566004).
Almost surely, 21223013132007 is an apocalyptic number.
1223013132007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1223013132007 is an equidigital number, since it uses as much as digits as its factorization.
1223013132007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 1223013132007 its reverse (7002313103221), we get a palindrome (8225326235228).
The spelling of 1223013132007 in words is "one trillion, two hundred twenty-three billion, thirteen million, one hundred thirty-two thousand, seven".
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