Base | Representation |
---|---|
bin | 1011000111111001011011… |
… | …1000101000100001000010 |
3 | 1121022012112212101221122212 |
4 | 2301332112320220201002 |
5 | 3100340130122221010 |
6 | 42002305045302122 |
7 | 2401416213643430 |
oct | 261762670504102 |
9 | 47265485357585 |
10 | 12230303320130 |
11 | 399592a420a25 |
12 | 1456393a04942 |
13 | 6a940ab94bcc |
14 | 303d42503d50 |
15 | 163211936505 |
hex | b1f96e28842 |
12230303320130 has 64 divisors (see below), whose sum is σ = 25342402176000. Its totient is φ = 4162764581568.
The previous prime is 12230303320129. The next prime is 12230303320189. The reversal of 12230303320130 is 3102330303221.
It is a junction number, because it is equal to n+sod(n) for n = 12230303320096 and 12230303320105.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 154268441 + ... + 154347699.
It is an arithmetic number, because the mean of its divisors is an integer number (395975034000).
Almost surely, 212230303320130 is an apocalyptic number.
12230303320130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12230303320130 is an abundant number, since it is smaller than the sum of its proper divisors (13112098855870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12230303320130 is a wasteful number, since it uses less digits than its factorization.
12230303320130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95271.
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 12230303320130 its reverse (3102330303221), we get a palindrome (15332633623351).
The spelling of 12230303320130 in words is "twelve trillion, two hundred thirty billion, three hundred three million, three hundred twenty thousand, one hundred thirty".
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