Search a number
-
+
122305433 = 1065111483
BaseRepresentation
bin1110100101000…
…11101110011001
322112010202111212
413102203232121
5222302233213
620045232505
73013402415
oct722435631
9275122455
10122305433
1163046978
1234b62735
131c4533a3
1412359d45
15ab0d9a8
hex74a3b99

122305433 has 4 divisors (see below), whose sum is σ = 122327568. Its totient is φ = 122283300.

The previous prime is 122305411. The next prime is 122305481. The reversal of 122305433 is 334503221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 122305433 - 26 = 122305369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 122305399 and 122305408.

It is not an unprimeable number, because it can be changed into a prime (122305133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4910 + ... + 16392.

It is an arithmetic number, because the mean of its divisors is an integer number (30581892).

Almost surely, 2122305433 is an apocalyptic number.

It is an amenable number.

122305433 is a deficient number, since it is larger than the sum of its proper divisors (22135).

122305433 is a wasteful number, since it uses less digits than its factorization.

122305433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22134.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 122305433 is about 11059.1786765564. The cubic root of 122305433 is about 496.3811145280.

Adding to 122305433 its reverse (334503221), we get a palindrome (456808654).

The spelling of 122305433 in words is "one hundred twenty-two million, three hundred five thousand, four hundred thirty-three".

Divisors: 1 10651 11483 122305433