Base | Representation |
---|---|
bin | 1011001000000000111100… |
… | …1001110110110101001011 |
3 | 1121022101202111012211211112 |
4 | 2302000033021312311023 |
5 | 3100403243200214011 |
6 | 42003241205320535 |
7 | 2401520214543035 |
oct | 262001711666513 |
9 | 47271674184745 |
10 | 12232321101131 |
11 | 399677540272a |
12 | 145685770614b |
13 | 6a966cc26671 |
14 | 3040944aac55 |
15 | 1632cdb5c58b |
hex | b200f276d4b |
12232321101131 has 2 divisors, whose sum is σ = 12232321101132. Its totient is φ = 12232321101130.
The previous prime is 12232321101127. The next prime is 12232321101163. The reversal of 12232321101131 is 13110112323221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12232321101131 - 22 = 12232321101127 is a prime.
It is a super-2 number, since 2×122323211011312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12232321101097 and 12232321101106.
It is not a weakly prime, because it can be changed into another prime (12232321101181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6116160550565 + 6116160550566.
It is an arithmetic number, because the mean of its divisors is an integer number (6116160550566).
Almost surely, 212232321101131 is an apocalyptic number.
12232321101131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12232321101131 is an equidigital number, since it uses as much as digits as its factorization.
12232321101131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 12232321101131 its reverse (13110112323221), we get a palindrome (25342433424352).
The spelling of 12232321101131 in words is "twelve trillion, two hundred thirty-two billion, three hundred twenty-one million, one hundred one thousand, one hundred thirty-one".
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