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12232434433 is a prime number
BaseRepresentation
bin10110110010001110…
…00010001100000001
31011120111111001110011
423121013002030001
5200023000400213
65341451304521
7612062656102
oct133107021401
934514431404
1012232434433
11520798804a
12245474b141
1311cc366bab
148408443a9
154b8d8503d
hex2d91c2301

12232434433 has 2 divisors, whose sum is σ = 12232434434. Its totient is φ = 12232434432.

The previous prime is 12232434427. The next prime is 12232434437. The reversal of 12232434433 is 33443423221.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8955215424 + 3277219009 = 94632^2 + 57247^2 .

It is a cyclic number.

It is not a de Polignac number, because 12232434433 - 221 = 12230337281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12232434395 and 12232434404.

It is not a weakly prime, because it can be changed into another prime (12232434437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6116217216 + 6116217217.

It is an arithmetic number, because the mean of its divisors is an integer number (6116217217).

Almost surely, 212232434433 is an apocalyptic number.

It is an amenable number.

12232434433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12232434433 is an equidigital number, since it uses as much as digits as its factorization.

12232434433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 31.

Adding to 12232434433 its reverse (33443423221), we get a palindrome (45675857654).

The spelling of 12232434433 in words is "twelve billion, two hundred thirty-two million, four hundred thirty-four thousand, four hundred thirty-three".