Base | Representation |
---|---|
bin | 11011110100001000101110… |
… | …110100110001100100011111 |
3 | 121001010122020002211220010111 |
4 | 123310020232310301210133 |
5 | 112013223412243024020 |
6 | 1112101351344350451 |
7 | 34524024350303410 |
oct | 3364105664614437 |
9 | 531118202756114 |
10 | 122330044111135 |
11 | 35a83975843703 |
12 | 11878470315427 |
13 | 533489b05a8a3 |
14 | 222cb3ccad807 |
15 | e22142730d5a |
hex | 6f422ed3191f |
122330044111135 has 16 divisors (see below), whose sum is σ = 167942958520896. Its totient is φ = 83795438377728.
The previous prime is 122330044111129. The next prime is 122330044111157. The reversal of 122330044111135 is 531111440033221.
It is a happy number.
It is not a de Polignac number, because 122330044111135 - 211 = 122330044109087 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 122330044111097 and 122330044111106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1833725364 + ... + 1833792073.
It is an arithmetic number, because the mean of its divisors is an integer number (10496434907556).
Almost surely, 2122330044111135 is an apocalyptic number.
122330044111135 is a deficient number, since it is larger than the sum of its proper divisors (45612914409761).
122330044111135 is an equidigital number, since it uses as much as digits as its factorization.
122330044111135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3667518402.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 122330044111135 its reverse (531111440033221), we get a palindrome (653441484144356).
The spelling of 122330044111135 in words is "one hundred twenty-two trillion, three hundred thirty billion, forty-four million, one hundred eleven thousand, one hundred thirty-five".
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