Base | Representation |
---|---|
bin | 10001110011010011000… |
… | …110011101111100010111 |
3 | 11022221120202002202000021 |
4 | 101303103012131330113 |
5 | 130020320433301101 |
6 | 2333552034130011 |
7 | 154244551556152 |
oct | 21632306357427 |
9 | 4287522082007 |
10 | 1223312400151 |
11 | 431892a5a3a6 |
12 | 179104a20907 |
13 | 8b4862c6b1a |
14 | 432cc6d6c99 |
15 | 21c4b6585a1 |
hex | 11cd319df17 |
1223312400151 has 4 divisors (see below), whose sum is σ = 1230637624272. Its totient is φ = 1215987176032.
The previous prime is 1223312400131. The next prime is 1223312400181. The reversal of 1223312400151 is 1510042133221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1223312400151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1223312400131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3662611810 + ... + 3662612143.
It is an arithmetic number, because the mean of its divisors is an integer number (307659406068).
Almost surely, 21223312400151 is an apocalyptic number.
1223312400151 is a deficient number, since it is larger than the sum of its proper divisors (7325224121).
1223312400151 is an equidigital number, since it uses as much as digits as its factorization.
1223312400151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7325224120.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1223312400151 its reverse (1510042133221), we get a palindrome (2733354533372).
The spelling of 1223312400151 in words is "one trillion, two hundred twenty-three billion, three hundred twelve million, four hundred thousand, one hundred fifty-one".
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