Base | Representation |
---|---|
bin | 1011001000000100101101… |
… | …1110110101010111110011 |
3 | 1121022111101000201110221012 |
4 | 2302001023132311113303 |
5 | 3100412331301430024 |
6 | 42003525443021135 |
7 | 2401554254533154 |
oct | 262011336652763 |
9 | 47274330643835 |
10 | 12233333233139 |
11 | 3997144762467 |
12 | 1456a9a66a7ab |
13 | 6a97a1820945 |
14 | 30414ca9592b |
15 | 16333c93850e |
hex | b204b7b55f3 |
12233333233139 has 2 divisors, whose sum is σ = 12233333233140. Its totient is φ = 12233333233138.
The previous prime is 12233333233133. The next prime is 12233333233141. The reversal of 12233333233139 is 93133233333221.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12233333233139 - 216 = 12233333167603 is a prime.
Together with 12233333233141, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 12233333233096 and 12233333233105.
It is not a weakly prime, because it can be changed into another prime (12233333233133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6116666616569 + 6116666616570.
It is an arithmetic number, because the mean of its divisors is an integer number (6116666616570).
Almost surely, 212233333233139 is an apocalyptic number.
12233333233139 is a deficient number, since it is larger than the sum of its proper divisors (1).
12233333233139 is an equidigital number, since it uses as much as digits as its factorization.
12233333233139 is an evil number, because the sum of its binary digits is even.
The product of its digits is 472392, while the sum is 41.
The spelling of 12233333233139 in words is "twelve trillion, two hundred thirty-three billion, three hundred thirty-three million, two hundred thirty-three thousand, one hundred thirty-nine".
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