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12234113027 is a prime number
BaseRepresentation
bin10110110010011010…
…11100000000000011
31011120121122100001022
423121031130000003
5200023413104102
65341551300055
7612113150003
oct133115340003
934517570038
1012234113027
115208924214
12245521a62b
1311cc803c46
14840b60003
154b90b75a2
hex2d935c003

12234113027 has 2 divisors, whose sum is σ = 12234113028. Its totient is φ = 12234113026.

The previous prime is 12234112987. The next prime is 12234113033. The reversal of 12234113027 is 72031143221.

It is a strong prime.

It is an emirp because it is prime and its reverse (72031143221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12234113027 - 26 = 12234112963 is a prime.

It is a super-2 number, since 2×122341130272 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12234112987 and 12234113005.

It is not a weakly prime, because it can be changed into another prime (12234113077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6117056513 + 6117056514.

It is an arithmetic number, because the mean of its divisors is an integer number (6117056514).

Almost surely, 212234113027 is an apocalyptic number.

12234113027 is a deficient number, since it is larger than the sum of its proper divisors (1).

12234113027 is an equidigital number, since it uses as much as digits as its factorization.

12234113027 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 12234113027 its reverse (72031143221), we get a palindrome (84265256248).

The spelling of 12234113027 in words is "twelve billion, two hundred thirty-four million, one hundred thirteen thousand, twenty-seven".