Base | Representation |
---|---|
bin | 10110110011001000… |
… | …00111000010110111 |
3 | 1011121000211021222001 |
4 | 23121210013002313 |
5 | 200031423302003 |
6 | 5342322520131 |
7 | 612214522633 |
oct | 133144070267 |
9 | 34530737861 |
10 | 12240056503 |
11 | 5211213684 |
12 | 2457206047 |
13 | 1200b052ac |
14 | 841869dc3 |
15 | 4b988d61d |
hex | 2d99070b7 |
12240056503 has 8 divisors (see below), whose sum is σ = 12291268608. Its totient is φ = 12188872704.
The previous prime is 12240056497. The next prime is 12240056531. The reversal of 12240056503 is 30565004221.
12240056503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12240056503 - 25 = 12240056471 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12240056903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1574875 + ... + 1582627.
It is an arithmetic number, because the mean of its divisors is an integer number (1536408576).
Almost surely, 212240056503 is an apocalyptic number.
12240056503 is a deficient number, since it is larger than the sum of its proper divisors (51212105).
12240056503 is an equidigital number, since it uses as much as digits as its factorization.
12240056503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14153.
The product of its (nonzero) digits is 7200, while the sum is 28.
The spelling of 12240056503 in words is "twelve billion, two hundred forty million, fifty-six thousand, five hundred three".
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