Base | Representation |
---|---|
bin | 10110110011010010… |
… | …10110101001001001 |
3 | 1011121010102010120112 |
4 | 23121221112221021 |
5 | 200032301243423 |
6 | 5342412204105 |
7 | 612232306352 |
oct | 133151265111 |
9 | 34533363515 |
10 | 12241431113 |
11 | 5211a7241a |
12 | 2457769635 |
13 | 1201196b82 |
14 | 841b06d29 |
15 | 4b9a60a78 |
hex | 2d9a56a49 |
12241431113 has 2 divisors, whose sum is σ = 12241431114. Its totient is φ = 12241431112.
The previous prime is 12241431091. The next prime is 12241431157. The reversal of 12241431113 is 31113414221.
12241431113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7469799184 + 4771631929 = 86428^2 + 69077^2 .
It is a cyclic number.
It is not a de Polignac number, because 12241431113 - 224 = 12224653897 is a prime.
It is not a weakly prime, because it can be changed into another prime (12241431173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6120715556 + 6120715557.
It is an arithmetic number, because the mean of its divisors is an integer number (6120715557).
Almost surely, 212241431113 is an apocalyptic number.
It is an amenable number.
12241431113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12241431113 is an equidigital number, since it uses as much as digits as its factorization.
12241431113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 576, while the sum is 23.
Adding to 12241431113 its reverse (31113414221), we get a palindrome (43354845334).
The spelling of 12241431113 in words is "twelve billion, two hundred forty-one million, four hundred thirty-one thousand, one hundred thirteen".
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