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12241443421551 = 34080481140517
BaseRepresentation
bin1011001000100010111011…
…1000101111110101101111
31121100021022020110201220210
42302020232320233311233
53101030434003442201
642011350320313503
72402262244151301
oct262105670576557
947307266421823
1012241443421551
11399a626750013
121458582772893
136aa494b33ab6
143046bbc43971
1516366494c1d6
hexb222ee2fd6f

12241443421551 has 4 divisors (see below), whose sum is σ = 16321924562072. Its totient is φ = 8160962281032.

The previous prime is 12241443421547. The next prime is 12241443421577. The reversal of 12241443421551 is 15512434414221.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12241443421551 - 22 = 12241443421547 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12241443428551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2040240570256 + ... + 2040240570261.

It is an arithmetic number, because the mean of its divisors is an integer number (4080481140518).

Almost surely, 212241443421551 is an apocalyptic number.

12241443421551 is a deficient number, since it is larger than the sum of its proper divisors (4080481140521).

12241443421551 is an equidigital number, since it uses as much as digits as its factorization.

12241443421551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4080481140520.

The product of its digits is 153600, while the sum is 39.

Adding to 12241443421551 its reverse (15512434414221), we get a palindrome (27753877835772).

The spelling of 12241443421551 in words is "twelve trillion, two hundred forty-one billion, four hundred forty-three million, four hundred twenty-one thousand, five hundred fifty-one".

Divisors: 1 3 4080481140517 12241443421551