Base | Representation |
---|---|
bin | 1011001000101101011000… |
… | …1111010100010001001001 |
3 | 1121100112112220200020221202 |
4 | 2302023112033110101021 |
5 | 3101102211242224001 |
6 | 42012533055313545 |
7 | 2402421646255046 |
oct | 262132617242111 |
9 | 47315486606852 |
10 | 12244251133001 |
11 | 39a08376151a8 |
12 | 1459026b1b8b5 |
13 | 6aa821731014 |
14 | 3048a6ab41cd |
15 | 16377b1ab96b |
hex | b22d63d4449 |
12244251133001 has 4 divisors (see below), whose sum is σ = 12251613883392. Its totient is φ = 12236888382612.
The previous prime is 12244251132959. The next prime is 12244251133069. The reversal of 12244251133001 is 10033115244221.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12244251133001 - 218 = 12244250870857 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12244241133001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3681372701 + ... + 3681376026.
It is an arithmetic number, because the mean of its divisors is an integer number (3062903470848).
Almost surely, 212244251133001 is an apocalyptic number.
It is an amenable number.
12244251133001 is a deficient number, since it is larger than the sum of its proper divisors (7362750391).
12244251133001 is an equidigital number, since it uses as much as digits as its factorization.
12244251133001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7362750390.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 12244251133001 its reverse (10033115244221), we get a palindrome (22277366377222).
The spelling of 12244251133001 in words is "twelve trillion, two hundred forty-four billion, two hundred fifty-one million, one hundred thirty-three thousand, one".
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