Base | Representation |
---|---|
bin | 1011001000101101111110… |
… | …1110010001100110100101 |
3 | 1121100112222000001220111221 |
4 | 2302023133232101212211 |
5 | 3101103023010242433 |
6 | 42013000541500341 |
7 | 2402425620551041 |
oct | 262133756214645 |
9 | 47315860056457 |
10 | 12244410243493 |
11 | 39a090940a27a |
12 | 14590702716b1 |
13 | 6aa84869c93c |
14 | 3048bdc91021 |
15 | 16378a13a72d |
hex | b22dfb919a5 |
12244410243493 has 2 divisors, whose sum is σ = 12244410243494. Its totient is φ = 12244410243492.
The previous prime is 12244410243487. The next prime is 12244410243623. The reversal of 12244410243493 is 39434201444221.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11096473712769 + 1147936530724 = 3331137^2 + 1071418^2 .
It is a cyclic number.
It is not a de Polignac number, because 12244410243493 - 213 = 12244410235301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12244410243293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6122205121746 + 6122205121747.
It is an arithmetic number, because the mean of its divisors is an integer number (6122205121747).
Almost surely, 212244410243493 is an apocalyptic number.
It is an amenable number.
12244410243493 is a deficient number, since it is larger than the sum of its proper divisors (1).
12244410243493 is an equidigital number, since it uses as much as digits as its factorization.
12244410243493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 663552, while the sum is 43.
The spelling of 12244410243493 in words is "twelve trillion, two hundred forty-four billion, four hundred ten million, two hundred forty-three thousand, four hundred ninety-three".
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