Base | Representation |
---|---|
bin | 10001110100011011110… |
… | …111100100100110001101 |
3 | 11100001201211022102111011 |
4 | 101310123313210212031 |
5 | 130030321001411023 |
6 | 2334313124525221 |
7 | 154320034506550 |
oct | 21643367444615 |
9 | 4301654272434 |
10 | 1224533232013 |
11 | 43235a0a4453 |
12 | 1793a5850811 |
13 | 8b61c203240 |
14 | 433a68ca697 |
15 | 21cbd90b50d |
hex | 11d1bde498d |
1224533232013 has 16 divisors (see below), whose sum is σ = 1595771815680. Its totient is φ = 911869606656.
The previous prime is 1224533231947. The next prime is 1224533232071. The reversal of 1224533232013 is 3102323354221.
It is a cyclic number.
It is not a de Polignac number, because 1224533232013 - 213 = 1224533223821 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1224533230013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 395775193 + ... + 395778286.
It is an arithmetic number, because the mean of its divisors is an integer number (99735738480).
Almost surely, 21224533232013 is an apocalyptic number.
1224533232013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1224533232013 is a deficient number, since it is larger than the sum of its proper divisors (371238583667).
1224533232013 is a wasteful number, since it uses less digits than its factorization.
1224533232013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 791553516.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 1224533232013 its reverse (3102323354221), we get a palindrome (4326856586234).
The spelling of 1224533232013 in words is "one trillion, two hundred twenty-four billion, five hundred thirty-three million, two hundred thirty-two thousand, thirteen".
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