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1224889013237 is a prime number
BaseRepresentation
bin10001110100110001000…
…100110001001111110101
311100002122121202222120112
4101310301010301033311
5130032033041410422
62334412314312405
7154331614552601
oct21646104611765
94302577688515
101224889013237
11432521a0811a
12179484a28705
138b677b31986
14433dbc60501
1521cdec87ee2
hex11d311313f5

1224889013237 has 2 divisors, whose sum is σ = 1224889013238. Its totient is φ = 1224889013236.

The previous prime is 1224889013233. The next prime is 1224889013239. The reversal of 1224889013237 is 7323109884221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 685958307076 + 538930706161 = 828226^2 + 734119^2 .

It is a cyclic number.

It is not a de Polignac number, because 1224889013237 - 22 = 1224889013233 is a prime.

It is a super-2 number, since 2×12248890132372 (a number of 25 digits) contains 22 as substring.

Together with 1224889013239, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1224889013233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612444506618 + 612444506619.

It is an arithmetic number, because the mean of its divisors is an integer number (612444506619).

Almost surely, 21224889013237 is an apocalyptic number.

It is an amenable number.

1224889013237 is a deficient number, since it is larger than the sum of its proper divisors (1).

1224889013237 is an equidigital number, since it uses as much as digits as its factorization.

1224889013237 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1161216, while the sum is 50.

The spelling of 1224889013237 in words is "one trillion, two hundred twenty-four billion, eight hundred eighty-nine million, thirteen thousand, two hundred thirty-seven".