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12250244055 = 3571031113161
BaseRepresentation
bin10110110100010101…
…11110001111010111
31011121201222212122210
423122022332033113
5200042030302210
65343325124503
7612400233150
oct133212761727
934551885583
1012250244055
115216a41745
12245a6b9733
131202c6132a
14842d5c927
154ba701e20
hex2da2be3d7

12250244055 has 32 divisors (see below), whose sum is σ = 22422371328. Its totient is φ = 5594630400.

The previous prime is 12250244033. The next prime is 12250244063. The reversal of 12250244055 is 55044205221.

It is not a de Polignac number, because 12250244055 - 25 = 12250244023 is a prime.

It is a super-3 number, since 3×122502440553 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 51675 + ... + 164835.

It is an arithmetic number, because the mean of its divisors is an integer number (700699104).

Almost surely, 212250244055 is an apocalyptic number.

12250244055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12250244055 is a deficient number, since it is larger than the sum of its proper divisors (10172127273).

12250244055 is a wasteful number, since it uses less digits than its factorization.

12250244055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114207.

The product of its (nonzero) digits is 16000, while the sum is 30.

Adding to 12250244055 its reverse (55044205221), we get a palindrome (67294449276).

The spelling of 12250244055 in words is "twelve billion, two hundred fifty million, two hundred forty-four thousand, fifty-five".

Divisors: 1 3 5 7 15 21 35 105 1031 3093 5155 7217 15465 21651 36085 108255 113161 339483 565805 792127 1697415 2376381 3960635 11881905 116668991 350006973 583344955 816682937 1750034865 2450048811 4083414685 12250244055