Base | Representation |
---|---|
bin | 10110110100010101… |
… | …11110001111010111 |
3 | 1011121201222212122210 |
4 | 23122022332033113 |
5 | 200042030302210 |
6 | 5343325124503 |
7 | 612400233150 |
oct | 133212761727 |
9 | 34551885583 |
10 | 12250244055 |
11 | 5216a41745 |
12 | 245a6b9733 |
13 | 1202c6132a |
14 | 842d5c927 |
15 | 4ba701e20 |
hex | 2da2be3d7 |
12250244055 has 32 divisors (see below), whose sum is σ = 22422371328. Its totient is φ = 5594630400.
The previous prime is 12250244033. The next prime is 12250244063. The reversal of 12250244055 is 55044205221.
It is not a de Polignac number, because 12250244055 - 25 = 12250244023 is a prime.
It is a super-3 number, since 3×122502440553 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 51675 + ... + 164835.
It is an arithmetic number, because the mean of its divisors is an integer number (700699104).
Almost surely, 212250244055 is an apocalyptic number.
12250244055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12250244055 is a deficient number, since it is larger than the sum of its proper divisors (10172127273).
12250244055 is a wasteful number, since it uses less digits than its factorization.
12250244055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 114207.
The product of its (nonzero) digits is 16000, while the sum is 30.
Adding to 12250244055 its reverse (55044205221), we get a palindrome (67294449276).
The spelling of 12250244055 in words is "twelve billion, two hundred fifty million, two hundred forty-four thousand, fifty-five".
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