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1225145070879 = 3408381690293
BaseRepresentation
bin10001110101000000010…
…101100011010100011111
311100010022110121001121220
4101311000111203110133
5130033044114232004
62334453542424423
7154341144164412
oct21650025432437
94303273531556
101225145070879
114326434a9004
12179536732113
138b6b8bb5682
1443423c75b79
1521d074b6dd9
hex11d4056351f

1225145070879 has 4 divisors (see below), whose sum is σ = 1633526761176. Its totient is φ = 816763380584.

The previous prime is 1225145070871. The next prime is 1225145070881. The reversal of 1225145070879 is 9780705415221.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1225145070879 - 23 = 1225145070871 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1225145070871) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204190845144 + ... + 204190845149.

It is an arithmetic number, because the mean of its divisors is an integer number (408381690294).

Almost surely, 21225145070879 is an apocalyptic number.

1225145070879 is a deficient number, since it is larger than the sum of its proper divisors (408381690297).

1225145070879 is an equidigital number, since it uses as much as digits as its factorization.

1225145070879 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 408381690296.

The product of its (nonzero) digits is 1411200, while the sum is 51.

The spelling of 1225145070879 in words is "one trillion, two hundred twenty-five billion, one hundred forty-five million, seventy thousand, eight hundred seventy-nine".

Divisors: 1 3 408381690293 1225145070879