Base | Representation |
---|---|
bin | 10001110101000110000… |
… | …001010111110011100111 |
3 | 11100010120010001112010201 |
4 | 101311012001113303213 |
5 | 130033243023203020 |
6 | 2334511230531331 |
7 | 154343412636511 |
oct | 21650601276347 |
9 | 4303503045121 |
10 | 1225240444135 |
11 | 43269231a384 |
12 | 179562666b47 |
13 | 8b702899256 |
14 | 434327c0bb1 |
15 | 21d10a55a0a |
hex | 11d46057ce7 |
1225240444135 has 8 divisors (see below), whose sum is σ = 1547672140080. Its totient is φ = 928603283904.
The previous prime is 1225240444079. The next prime is 1225240444139. The reversal of 1225240444135 is 5314440425221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1225240444135 - 213 = 1225240435943 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1225240444094 and 1225240444103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1225240444139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6448633822 + ... + 6448634011.
It is an arithmetic number, because the mean of its divisors is an integer number (193459017510).
Almost surely, 21225240444135 is an apocalyptic number.
1225240444135 is a deficient number, since it is larger than the sum of its proper divisors (322431695945).
1225240444135 is a wasteful number, since it uses less digits than its factorization.
1225240444135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12897267857.
The product of its (nonzero) digits is 153600, while the sum is 37.
Adding to 1225240444135 its reverse (5314440425221), we get a palindrome (6539680869356).
The spelling of 1225240444135 in words is "one trillion, two hundred twenty-five billion, two hundred forty million, four hundred forty-four thousand, one hundred thirty-five".
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