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12254001430207 is a prime number
BaseRepresentation
bin1011001001010001101101…
…1001101111111010111111
31121101110201102120200020111
42302110123121233322333
53101232143331231312
642021224402130451
72403215402363365
oct262243331577277
947343642520214
1012254001430207
1139a4990389869
12145aaa8350a27
136ab716781154
1430514d9d7635
15163b4c1938a7
hexb251b66febf

12254001430207 has 2 divisors, whose sum is σ = 12254001430208. Its totient is φ = 12254001430206.

The previous prime is 12254001430067. The next prime is 12254001430247. The reversal of 12254001430207 is 70203410045221.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12254001430207 - 231 = 12251853946559 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12254001430247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6127000715103 + 6127000715104.

It is an arithmetic number, because the mean of its divisors is an integer number (6127000715104).

Almost surely, 212254001430207 is an apocalyptic number.

12254001430207 is a deficient number, since it is larger than the sum of its proper divisors (1).

12254001430207 is an equidigital number, since it uses as much as digits as its factorization.

12254001430207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13440, while the sum is 31.

Adding to 12254001430207 its reverse (70203410045221), we get a palindrome (82457411475428).

The spelling of 12254001430207 in words is "twelve trillion, two hundred fifty-four billion, one million, four hundred thirty thousand, two hundred seven".