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122555345105159 is a prime number
BaseRepresentation
bin11011110111011010100011…
…110011110111000100000111
3121001221011202201102020121122
4123313122203303313010013
5112030421321321331114
61112353052010504155
734546221462201401
oct3367324363670407
9531834681366548
10122555345105159
113606048033411a
12118b406913505b
13534cbc506b635
1422399d32c9b71
15e27e2bed0e8e
hex6f76a3cf7107

122555345105159 has 2 divisors, whose sum is σ = 122555345105160. Its totient is φ = 122555345105158.

The previous prime is 122555345105117. The next prime is 122555345105161. The reversal of 122555345105159 is 951501543555221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 122555345105159 - 232 = 122551050137863 is a prime.

It is a super-2 number, since 2×1225553451051592 (a number of 29 digits) contains 22 as substring.

Together with 122555345105161, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 122555345105159.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122555345105659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61277672552579 + 61277672552580.

It is an arithmetic number, because the mean of its divisors is an integer number (61277672552580).

Almost surely, 2122555345105159 is an apocalyptic number.

122555345105159 is a deficient number, since it is larger than the sum of its proper divisors (1).

122555345105159 is an equidigital number, since it uses as much as digits as its factorization.

122555345105159 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6750000, while the sum is 53.

The spelling of 122555345105159 in words is "one hundred twenty-two trillion, five hundred fifty-five billion, three hundred forty-five million, one hundred five thousand, one hundred fifty-nine".