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1225646533 is a prime number
BaseRepresentation
bin100100100001101…
…1110000111000101
310011102021021222001
41021003132013011
510002231142113
6321341505301
742241552336
oct11103360705
93142237861
101225646533
11579933421
122a2572231
13166c03a47
14b8ac828d
15729047dd
hex490de1c5

1225646533 has 2 divisors, whose sum is σ = 1225646534. Its totient is φ = 1225646532.

The previous prime is 1225646531. The next prime is 1225646537. The reversal of 1225646533 is 3356465221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1223390529 + 2256004 = 34977^2 + 1502^2 .

It is an emirp because it is prime and its reverse (3356465221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1225646533 - 21 = 1225646531 is a prime.

It is a super-3 number, since 3×12256465333 (a number of 28 digits) contains 333 as substring.

Together with 1225646531, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1225646492 and 1225646501.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1225646531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612823266 + 612823267.

It is an arithmetic number, because the mean of its divisors is an integer number (612823267).

Almost surely, 21225646533 is an apocalyptic number.

It is an amenable number.

1225646533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1225646533 is an equidigital number, since it uses as much as digits as its factorization.

1225646533 is an evil number, because the sum of its binary digits is even.

The product of its digits is 129600, while the sum is 37.

The square root of 1225646533 is about 35009.2349673625. The cubic root of 1225646533 is about 1070.1756875169.

The spelling of 1225646533 in words is "one billion, two hundred twenty-five million, six hundred forty-six thousand, five hundred thirty-three".