12262334413031 has 2 divisors, whose sum is σ = 12262334413032. Its totient is φ = 12262334413030.

The previous prime is 12262334413013. The next prime is 12262334413033. The reversal of 12262334413031 is 13031443326221.

Together with previous prime (12262334413013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12262334413031 - 2¹⁸ = 12262334150887 is a prime.

It is a super-2 number, since 2×12262334413031² (a number of 27 digits) contains 22 as substring.

Together with 12262334413033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12262334412982 and 12262334413000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12262334413033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6131167206515 + 6131167206516.

It is an arithmetic number, because the mean of its divisors is an integer number (6131167206516).

Almost surely, 2^{12262334413031} is an apocalyptic number.

12262334413031 is a deficient number, since it is larger than the sum of its proper divisors (1).

12262334413031 is an equidigital number, since it uses as much as digits as its factorization.

12262334413031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 12262334413031 its reverse (13031443326221), we get a palindrome (25293777739252).

The spelling of 12262334413031 in words is "twelve trillion, two hundred sixty-two billion, three hundred thirty-four million, four hundred thirteen thousand, thirty-one".