Base | Representation |
---|---|
bin | 10110110111100110… |
… | …01000100001001101 |
3 | 1011200122101010011222 |
4 | 23123303020201031 |
5 | 200121023033013 |
6 | 5350142253125 |
7 | 613151305613 |
oct | 133363104115 |
9 | 34618333158 |
10 | 12277549133 |
11 | 52303a1423 |
12 | 24678871a5 |
13 | 1208801795 |
14 | 8468296b3 |
15 | 4bcce7508 |
hex | 2dbcc884d |
12277549133 has 2 divisors, whose sum is σ = 12277549134. Its totient is φ = 12277549132.
The previous prime is 12277549129. The next prime is 12277549159. The reversal of 12277549133 is 33194577221.
12277549133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11465698084 + 811851049 = 107078^2 + 28493^2 .
It is a cyclic number.
It is not a de Polignac number, because 12277549133 - 22 = 12277549129 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12277549033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6138774566 + 6138774567.
It is an arithmetic number, because the mean of its divisors is an integer number (6138774567).
Almost surely, 212277549133 is an apocalyptic number.
It is an amenable number.
12277549133 is a deficient number, since it is larger than the sum of its proper divisors (1).
12277549133 is an equidigital number, since it uses as much as digits as its factorization.
12277549133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 317520, while the sum is 44.
The spelling of 12277549133 in words is "twelve billion, two hundred seventy-seven million, five hundred forty-nine thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •