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122812243901341 is a prime number
BaseRepresentation
bin11011111011001001110100…
…001010111111101110011101
3121002211201212102211020222121
4123323021310022333232131
5112044123433414320331
61113111055503342541
734603614615012511
oct3373116412775635
9532751772736877
10122812243901341
113614a41aa79015
1211935a03bb1a51
13536b1b648aa37
142248204032141
15e2e9657c2c11
hex6fb2742bfb9d

122812243901341 has 2 divisors, whose sum is σ = 122812243901342. Its totient is φ = 122812243901340.

The previous prime is 122812243901339. The next prime is 122812243901363. The reversal of 122812243901341 is 143109342218221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89954241705241 + 32858002196100 = 9484421^2 + 5732190^2 .

It is an emirp because it is prime and its reverse (143109342218221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 122812243901341 - 21 = 122812243901339 is a prime.

Together with 122812243901339, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122812343901341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61406121950670 + 61406121950671.

It is an arithmetic number, because the mean of its divisors is an integer number (61406121950671).

Almost surely, 2122812243901341 is an apocalyptic number.

It is an amenable number.

122812243901341 is a deficient number, since it is larger than the sum of its proper divisors (1).

122812243901341 is an equidigital number, since it uses as much as digits as its factorization.

122812243901341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 43.

The spelling of 122812243901341 in words is "one hundred twenty-two trillion, eight hundred twelve billion, two hundred forty-three million, nine hundred one thousand, three hundred forty-one".