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1228250553143 is a prime number
BaseRepresentation
bin10001110111111001011…
…100000001101100110111
311100102022220002220102112
4101313321130001230313
5130110424120200033
62340130040001235
7154511123304515
oct21677134015467
94312286086375
101228250553143
11433997464879
1217a06276021b
138ba923acb43
144363a4994b5
1521e39e44c48
hex11df9701b37

1228250553143 has 2 divisors, whose sum is σ = 1228250553144. Its totient is φ = 1228250553142.

The previous prime is 1228250553133. The next prime is 1228250553193. The reversal of 1228250553143 is 3413550528221.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1228250553143 - 214 = 1228250536759 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1228250553143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1228250553133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 614125276571 + 614125276572.

It is an arithmetic number, because the mean of its divisors is an integer number (614125276572).

Almost surely, 21228250553143 is an apocalyptic number.

1228250553143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1228250553143 is an equidigital number, since it uses as much as digits as its factorization.

1228250553143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 41.

The spelling of 1228250553143 in words is "one trillion, two hundred twenty-eight billion, two hundred fifty million, five hundred fifty-three thousand, one hundred forty-three".