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12300085555 = 53536968887
BaseRepresentation
bin10110111010010010…
…00110100100110011
31011202012210002100021
423131021012210303
5200142310214210
65352305304311
7613544000512
oct133511064463
934665702307
1012300085555
11524209436a
122473335097
131210392544
14849814679
154bec99bda
hex2dd246933

12300085555 has 8 divisors (see below), whose sum is σ = 14801918112. Its totient is φ = 9812191488.

The previous prime is 12300085547. The next prime is 12300085561. The reversal of 12300085555 is 55558000321.

12300085555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12300085555 - 23 = 12300085547 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12300085555.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3482679 + ... + 3486208.

It is an arithmetic number, because the mean of its divisors is an integer number (1850239764).

Almost surely, 212300085555 is an apocalyptic number.

12300085555 is a deficient number, since it is larger than the sum of its proper divisors (2501832557).

12300085555 is an equidigital number, since it uses as much as digits as its factorization.

12300085555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6969245.

The product of its (nonzero) digits is 30000, while the sum is 34.

Adding to 12300085555 its reverse (55558000321), we get a palindrome (67858085876).

The spelling of 12300085555 in words is "twelve billion, three hundred million, eighty-five thousand, five hundred fifty-five".

Divisors: 1 5 353 1765 6968887 34844435 2460017111 12300085555