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123001213200000 = 27355118786353
BaseRepresentation
bin11011111101111001110011…
…100111101010011010000000
3121010111210122000220020220220
4123331321303213222122000
5112110222441034400000
61113333551031303040
734623354504364422
oct3375716347523200
9533453560806826
10123001213200000
1136212581242013
121196656151aa80
135382c703c32a5
14225340d130812
15e348256411a0
hex6fde739ea680

123001213200000 has 384 divisors, whose sum is σ = 408725101794240. Its totient is φ = 32772311040000.

The previous prime is 123001213199993. The next prime is 123001213200007. The reversal of 123001213200000 is 2312100321.

It is an interprime number because it is at equal distance from previous prime (123001213199993) and next prime (123001213200007).

It is a tau number, because it is divible by the number of its divisors (384).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is not an unprimeable number, because it can be changed into a prime (123001213200007) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1424356824 + ... + 1424443176.

Almost surely, 2123001213200000 is an apocalyptic number.

123001213200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 123001213200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (204362550897120).

123001213200000 is an abundant number, since it is smaller than the sum of its proper divisors (285723888594240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123001213200000 is an frugal number, since it uses more digits than its factorization.

123001213200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87582 (or 87550 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 123001213200000 its reverse (2312100321), we get a palindrome (123003525300321).

The spelling of 123001213200000 in words is "one hundred twenty-three trillion, one billion, two hundred thirteen million, two hundred thousand".