Base | Representation |
---|---|
bin | 10001111001100010011… |
… | …111101110100101110010 |
3 | 11100120212201201010212102 |
4 | 101321202133232211302 |
5 | 130123031330143442 |
6 | 2341021002100402 |
7 | 154602605052026 |
oct | 21714237564562 |
9 | 4316781633772 |
10 | 1230013131122 |
11 | 434711389796 |
12 | 17a474aaa702 |
13 | 8bcb35c98a9 |
14 | 437665d0386 |
15 | 21edea5a232 |
hex | 11e627ee972 |
1230013131122 has 4 divisors (see below), whose sum is σ = 1845019696686. Its totient is φ = 615006565560.
The previous prime is 1230013131089. The next prime is 1230013131167. The reversal of 1230013131122 is 2211313100321.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1218681315721 + 11331815401 = 1103939^2 + 106451^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1230013131094 and 1230013131103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 307503282779 + ... + 307503282782.
Almost surely, 21230013131122 is an apocalyptic number.
1230013131122 is a deficient number, since it is larger than the sum of its proper divisors (615006565564).
1230013131122 is an equidigital number, since it uses as much as digits as its factorization.
1230013131122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 615006565563.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1230013131122 its reverse (2211313100321), we get a palindrome (3441326231443).
The spelling of 1230013131122 in words is "one trillion, two hundred thirty billion, thirteen million, one hundred thirty-one thousand, one hundred twenty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •