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123002022133 = 316177389029
BaseRepresentation
bin111001010001101111…
…1011110100011110101
3102202111020000010200101
41302203133132203311
54003402004202013
6132301212114101
711613050636344
oct1624337364365
9382436003611
10123002022133
114818a486851
121ba09165931
13b7a3129123
145d4bd17b5b
1532ed7e88dd
hex1ca37de8f5

123002022133 has 4 divisors (see below), whose sum is σ = 123002727340. Its totient is φ = 123001316928.

The previous prime is 123002022127. The next prime is 123002022151. The reversal of 123002022133 is 331220200321.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 75195511524 + 47806510609 = 274218^2 + 218647^2 .

It is a cyclic number.

It is not a de Polignac number, because 123002022133 - 233 = 114412087541 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 123002022133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123002022233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121663 + ... + 510691.

It is an arithmetic number, because the mean of its divisors is an integer number (30750681835).

Almost surely, 2123002022133 is an apocalyptic number.

It is an amenable number.

123002022133 is a deficient number, since it is larger than the sum of its proper divisors (705207).

123002022133 is an equidigital number, since it uses as much as digits as its factorization.

123002022133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 705206.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 123002022133 its reverse (331220200321), we get a palindrome (454222222454).

It can be divided in two parts, 1230020 and 22133, that added together give a triangular number (1252153 = T1582).

The spelling of 123002022133 in words is "one hundred twenty-three billion, two million, twenty-two thousand, one hundred thirty-three".

Divisors: 1 316177 389029 123002022133